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Match the following and choose the correct option given below (a) `N_(2)toN_(2)^(+)` (p) bond order increases (b) `N_(2)toN_(2)^(-)` (q) bond order decreases ( c) `O_(2)toO_(2)^(+)` ( r) paramagnetism decreases (d) `O_(2)toO_(2)^(-)` (s) paramagnetism desreases (t) No change in bond orderA. `{:(a,b,c,d),(s,p,r,q):}`B. `{:(a,b,c,d),(s,p,q,r):}`C. `{:(a,b,c,d),(r,q,s,p):}`D. `{:(a,b,c,d),(p,s,q,r):}` |
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Answer» Correct Answer - B (a)`N_2=sigma1s^2 sigma^**1s^2 sigma2s^2 sigma^**2s^2 pi2p_x^2 =pi2p_y^2 sigma2p_z^2` B.O.`=(10-4)/2=3` , n=0(D) `N_2^(+)=sigma1s^2 sigma^(**)1s^2 sigma2s^2 sigma^** 2s^2 sigma^** 2s^2 pi2p_x^2 = pi 2p_y^2 sigma2p_z^1` B.O.=`(9-4)/2=2.5` , n=1(P) (b)`O_2^+=sigma1s^2 sigma^**1s^2 sigma2s^2 sigma^**2s^2 sigma2p_z^2 pi2p_x^2 =pi2p_y^2 pi^(.)2p_x^1=pi^(.)2p_y^0` B.O.`=(10-5)/2=2.5` , n=1(P) `O_2^(2+)=sigma1s^2 sigma^(**)1s^2 sigma2s^2 sigma^** 2s^2 sigma^** 2p_z^2 pi2p_x^2 = pi 2p_y^2 sigma^(.)2p_x^0=pi^(.)2p_y^0` B.O.=`(10-4)/2=3` , n=1(D) (c )`B_2=sigma1s^2 sigma^**1s^2 sigma2s^2 sigma^**2s^2 pi2p_x^1 =pi2p_y^1 ` B.O.`=(6-4)/2=1` , n=2(P) `B_2^(+)=sigma1s^2 sigma^(**)1s^2 sigma2s^2 sigma^** 2s^2 pi2p_x^2 = pi 2p_y^1 sigma2p_z^0` B.O.=`(5-4)/2=1//2` , n=1(P) (d )`NO^(-)=sigma1s^2 sigma^**1s^2 sigma2s^2 sigma^**2s^2 sigma2p_z^2 pi2p_x^2 =pi2p_y^2 pi^(.)2p_x^1=pi^(.)2p_y^1 ` B.O.`=(10-6)/2=2.0` , n=2(P) `NO=sigma1s^2 sigma^(**)1s^2 sigma2s^2 sigma^** 2s^2 sigma 2p_z^2 pi2p_x^2 = pi 2p_y^2 pi^(**)2p_x^1=pi^(.)2p_y^0` B.O.=`(10-5)/2=2.5` , n=1(P) |
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