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Match the following lists: |
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Answer» `=cot^(-1)(-1-(x-1)^(2))` Now` -OO lt -1 -(x-1)^(2) lt -1` ` :. Cot^(-1) (-1-(x-1)^(2)) in [(3pi)/(4),pi)` Also, `f(0)=f(2)` So, `f(x)` is onto and many-one. B. Clearly, from the graph, `f(x)` is many-one and onto. c. d. Clearly, `f(x)` is INVERSE to itself. So, `f(x)` is BIJECTIVE. |
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