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Answer» or `[underset(xto0)lim100(sinx)/(x)]=99` and `[underset(xto0)lim100(x)/(sinx)]=100` ALSO, `underset(xto0)lim(sin^(-1)x)/(x)=1""`(but a value is more than 1) or `[underset(xto0)lim100(sin^(-1)x)/(x)]=100` and `[underset(xto0)lim100(x)/(sin^(-1)x)]=99` `underset(xto0)lim(tanx)/(x)=1""`(but a value is bigger than 1) or `[underset(xto0)lim100(tanx)/(x)]=100` and `[underset(xto0)lim100(tan^(-1)x)/(x)]=99` Hence, a. `underset(xto0)lim([100(sinx)/(x)]+[100(tanx)/(x)])=199` b. `underset(xto0)lim([100(x)/(sinx)]+[100(tanx)/(x)])=200` c. `underset(xto0)lim([100(sin^(-1)x)/(x)]+[100(tan^(-1)x)/(x)])=199` d. `underset(xto0)lim([100(x)/(sin^(-1)x)]+[100(tan^(-1)x)/(x)])=198` |
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