1.

Match the followings . `{:(,"List - I" ,, ,"List- II") , (,(A) "Potential of" ,, (I), 0.76 V), (, "Hydrogen electrode at pH = 10 " ,, (II) , 0.0592 V), (, (B) Cu^(2+)|Cu ,, (III) , -0.592 V), (, (C) Zn|Zn^(2+) ,, (IV) , 0.337 V), (, (D) (2.303RT)/(F) ,, (V) , -.76V):}` The correct is -A. `{:( A, B , C , D) , (V , I , IV , II):}`B. `{:( A, B , C , D) , (III , I , II , V):}`C. `{:( A, B , C , D) , (II , V , I , IV):}`D. `{:( A, B , C , D) , (III , IV , I , II):}`

Answer» Correct Answer - D
(A) pH = 10 `therefore [H^(+)] = 0 - (0.0592)/(1) "log" (1)/(10^(-10))`
= `-0.0592 xx log 10^(10) = -0.0592 xx 10 = -0.592 V `
(B) `Cu^(2+) | Cu , E_("Red")^(@) = +0.337 V`
(C) `Zn^(2+) | Zn = E_(Red)^(@) = -0.76 V`
(D) `(2.303 RT)/(F) = 0.0592 V `


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