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    				| 1. | Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II and assign the correct code : A. `{:(1,2,3,4),(iv,I,ii,iii):}`B. `{:(1,2,3,4),(I,ii,iii,iv):}`C. `{:(1,2,3,4),(iv,v,ii,i):}`D. `{:(1,2,3,4),(iii,v,I,ii):}` | 
| Answer» Correct Answer - C Key Concept Spin magnetic moment can be calculated as `mu=sqrt(n(n+2))BM` where, `mu`=magnetic moment BM=Bohr Magneton (unit of `mu`) n=number of upaired electrons in d-orbital. The electronic configuration of `CO^(3+)` is `[Ar]3d^(6)`. Here, n=4 `mu=sqrt(4(4+2))+sqrt(24)BM` The electronic configuration of `Cr^(3+) " is" [Ar]3d^(3)` Here, n=3 `mu=sqrt(3(3+2))=sqrt(15)BM` The electronic configuration of `Fe^(3+) " is " [Ar]3d^(5)`. Here, n=5 `mu=sqrt(5(5+2))=sqrt(35)BM` The electronic configuration of `Ni^(2+) " is" [Ar]3d^(8)`. Here, n=2 `mu=sqrt(2(2+2))=sqrt(8)BM` So, the correct option is ( c)`. | |