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Match the species given in Column-I with the hybridizations given in Column-II. |
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Answer» (B) In `[Al(H_2O)_6]^(3+)`coordination number of Al is 6 and geometry is octahedral. (C) In `B_2H_6`, each B atom uses `sp^3` hybrid orbitals for bonding. Out of the four, `sp^3` hybrids on each B atom, one is without an electron. (D) All the carbon atoms are equal and they undergo `sp^2` hybridization. Each carbon atom FORMS three sigma bonds with other three carbon atoms. (E) The basic structural unit of silicates is `SiO_4^(4-)`in which silicon atom is BONDED to four oxygen atoms in tetrahedron fashion. (F) In `[GeCl_6]^(2-)` , Ge has coordination number 6 and it has octahedral geometry and central atom Ge is `sp^3d^2` hybridized. |
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