Match the species given in Column I with the properties mentioned in Column II {:(,"Column-I",,"Column-II"),("A.","BF"_(4)^(-),1.,"Oxidation state of central atom is +4"),("B.","AlCl"_(3),2.,"Strong oxidising agent"),("C.","SnO",3.,"Lewis acid"),("D.","PbO"_(2),4.,"Can be further oxidised"),(,,5.,"Tetrahedral shape"):}

Match the species given in Column I with the properties mentioned in C

1.	Match the species given in Column I with the properties mentioned in Column II {:(,"Column-I",,"Column-II"),("A.","BF"_(4)^(-),1.,"Oxidation state of central atom is +4"),("B.","AlCl"_(3),2.,"Strong oxidising agent"),("C.","SnO",3.,"Lewis acid"),("D.","PbO"_(2),4.,"Can be further oxidised"),(,,5.,"Tetrahedral shape"):}
Answer» Solution :A. `BF_(4)^(-)` Tetrahedral shape `sp^(3)` HYBRIDISATION regular geometry B. `AlCl_(3^(-))` Octet not complete of Al, act as Lewis acid C. `SnO Sn^(2+)` can show +4 oxidation state D. `PbO_(2)` Oxidation state of PB in `PbO_(2)` is +4. Due to inert pair effect `Pb^(4+)` is less stable than `Pb^(2+)`, ACTS as strong oxidising agent.