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Match the species in Column I with the bond order in Column II : |
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Answer» Solution :(A - 5)(B - 1)(C - 2)(D - 3) (A) NO (7 + 8 = 15) = `sigma 1S^(2) , sigma^(**) 1s^(2), sigma 2S^(2), sigma^(**) 2s^(2), sigma 2p_(z)^(2) pi 2p_(x)^(2) = pi 2p_(y)^(2) pi^(**) 2p_(x)^(1)` Bond order= `(1)/(2) (N_(b) - N_(a)) (10 - 5)/(2)` = 2.5 (B) CO (6 + 8 = 14) = `sigma 1s^(2) , sigma^(**) 1s^(2) , sigma 2s^(2) , sigma^(**) 2s^(2) , sigma 2p_(z)^(2) , pi 2p_(x)^(2) = pi 2p_(y)^(2)` Bond order = `(10 - 4)/(2)` = 3 (C) `O_(2)^(-) (8 + 8 + - 16) = sigma 1s^(2), sigma^(**) 1s^(2) sigma 2s^(2), sigma^(**) 2s^(2), sigma 2p_(z)^(2), pi 2p_(x)^(2) = pi 2p_(y)^(1)` Bond order = `(10 - 7)/(2) ` = 1.5 (D) `O_(2) ( 8 + 8= 16) = sigma 1s^(2), sigma^(**) 1s^(2) , sigma 2s^(2) , sigma^(**) 2s^(2), sigma 2p_(x)^(2) , pi 2p_(x)^(2) = pi 2p_(y)^(2) , pi^(**) 2p_(x)^(1) = pi^(**) 2p_(y)^(1)` Bond order= `(10 - 6)/(2)` = 2 |
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