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Match the species in Column-I with the type of hybrid orbitals in Column-II : |
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Answer» Solution :(A - 3)(B- 1)(C - 5)(D -4) (A) `SF_(4)` = NUMBER of bp (4) + number of lp (1) = `sp^(3) ` d hybridization (B) `IF_(5)` = number of bp (5) + number of lp (1) = `sp^(3)d^(2)` hybridization (C) `NO_(2)^(+)` = number of bp (2) + number of lp (0) = sp hybridization (D) `NH_(4)^(+) = ` number of HP (4) + number of lp (0) = `sp^(3)` hybridization |
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