Maximum allowable current for a 240-V DC shunt motor is equal to 65 A. Minimum allowable current for same is equal to 40 A. What will be the value of γ?(a) 0.6153(b) 1.265(c) 1.625(d) 2.652I got this question in quiz.This intriguing question comes from Starting of DC Motors in section DC Motors of DC Machines

Maximum allowable current for a 240-V DC shunt motor is equal to 65 A.

1.	Maximum allowable current for a 240-V DC shunt motor is equal to 65 A. Minimum allowable current for same is equal to 40 A. What will be the value of γ?(a) 0.6153(b) 1.265(c) 1.625(d) 2.652I got this question in quiz.This intriguing question comes from Starting of DC Motors in section DC Motors of DC Machines
Answer» Right ANSWER is (c) 1.625 For explanation: γ is DEFINED as the RATIO of upper limit current value to the lower limit current value. So, γ will be the ratio of 65/40. From calculations, we get γ= 1.625. Note that γ is unitless quantity.

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