Maximum speed of a particle in simple harmonic motion is v_(max). Then average speed of this particle in one time period is equal to

Maximum speed of a particle in simple harmonic motion is v_(max). Then

1.	Maximum speed of a particle in simple harmonic motion is v_(max). Then average speed of this particle in one time period is equal to
Answer» `v_(max)/2` `v_(max)/PI` `(piv_(max))/2` `(2v_(max))/(pi)` ANSWER :D