InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Maximum velocity ini SHM is `v_(m)`. The average velocity during motion from one extreme point to the other extreme point will beA. `(4)/(pi)V_(max)`B. `(pi)/(4)V_(max)`C. `(2)/(pi)V_(max)`D. `(pi)/(2)V_(max)` |
|
Answer» Correct Answer - C `v_(max)=Aomega=(2piA)/(T)` and A, Amplitue, T, Period `rArr" "(A)/(T)=(V_(max))/(2pi)` `"Average velocity"=("Total displacement")/("Total time")=(2A)/(T//2)=(4A)/(T)` But `((A)/(T)=(V_(max))/(2pi))` `therefore` Average velocity `= 4 ((V_(max))/(2pi))=(2)/(pi)V_(max)` |
|