Mean of 100 observations is found to be 40. If at the time of computation two items are wrongly taken as 30 and 27 instead of 3 and 72, find thecorrect mean.

Mean of 100 observations is found to be 40. If at the time of computat

1.	Mean of 100 observations is found to be 40. If at the time of computation two items are wrongly taken as 30 and 27 instead of 3 and 72, find thecorrect mean.
Answer» Solution :GIVEN: `N = 100, BARX = 40 ` `barX = (sumX)/N` Or,`""40 = (sumX)/100` `:.""sumX("Wrong") = 40xx 100 = 4,000` Correct values = 3 + 72 = 75 Incorrect values = 30 + 27 = 57 `"Correct "barX=(sumX"(Wrong)+(Correct Value)-(Incorrect Value)")/N` ` = (4,000+75-57)/100=(4,018)/100=40.18` Corrected Mean = `40.18`.