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Medians QT and RS of `Triangle PQR` intersect at X. Show that `ar(triangle XQR)` is equal to `ar (quad SXTP)` |
Answer» ST||QR `/_QSP` and`/_QTR` `ar(/_QSR)=ar(/_QTR)` `/_QSR-/_XQR=/_QTR-/_XQR` `ar(/_QSX)=ar(/_TXR)` Area of`(/_PTQ)`=area of `(/_RTQ)` `ar(/_PTQ)-ar(/_QSX)=ar(/_RTQ)-ar(/_TXR)` `ar(PSXT)=ar(AXQR)` proved. |
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