1.

Mee app ko bro bhulaa aya apa bol doo.​

Answer»

Given :FATHER is now 3 TIMES as old as his son.Four years ago he was four times as old as his son.To FIND :Present Age of his son .Solution :\longmapsto\tt{Let\:Present\:age\:of\:his\:son\:be=x}⟼LetPresentageofhissonbe=xAs Given that Father is 3 times as old as his son. So ,\longmapsto\tt{Father=3x}⟼Father=3xBefore 4 years :\longmapsto\tt{Age\:of\:son=x-4}⟼Ageofson=x−4\longmapsto\tt{Age\:of\:father=3x-4}⟼Ageoffather=3x−4A.T Q :\longmapsto\tt{3x-4=4(x-4)}⟼3x−4=4(x−4)\longmapsto\tt{3x-4=4x-16}⟼3x−4=4x−16\longmapsto\tt{3x-4x=-16+4}⟼3x−4x=−16+4\longmapsto\tt{-x=-12}⟼−x=−12\longmapsto\tt\bf{x=12}⟼x=12So , The Present Age of his son is 12 years .Option 4) 12 years is Correct .


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