1.

Mention expression for K.E, P.E and total energy of a particle executing SHM.

Answer»

Potential energy of particle at any instant t second is Ep = \(\frac{1}{2}\) m ω2 y2.

Kinetic energy of particle at any instant t second is, EK = \(\frac{1}{2}\) m ω2 (A2 – y2).

Total energy of particle at any instant is constant E = EK + Ep = \(\frac{1}{2}\)m ω2 A2 .

A is the amplitude and w is the angular frequency and m is mass of the particle y is the displacement of a particle from its mean position in t seconds.



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