Saved Bookmarks
| 1. |
Mercury has an angle of contact equal to 140^@ with soda lime glass. A narrow tube of radius 1.00mm made of this glass is dipped in a trough containing mercury.By what amount does the mercury at the temperature of the experiment is 0.465 Nm^-1. Density of mercury =13.6 times 10^3 kg m^-3 |
|
Answer» Solution :RADIUS of tube, r = 1.00 mm = `10^(-3)m`, Surface tension of mercury, `alpha=0.465Nm^(-1)` Angle of CONTACT, `theta=140^(@)thereforeh=(2sigmacostheta)/(rrhog)=-5.24xx10^(-3)m=-5.24mm` NEGATIVE sign shows that the mercury LEVEL is depressed in the tube. |
|