1.

Meta-directing and deactivating group in aromatic electrophilic substitution is

Answer»

`-CH_(3)`
`-OH`
`-NO_(2)`
`-CL`

SOLUTION :`-CH_(3) ""` Activaing and o, p-directing
`-OH ""` ACTIVATING and o, p-directing
`-NO_(2) ""` DEACTIVATING and m-directing
`-Cl ""` Deactivating and o, p-directing
`-OCH_(3) ""` Activating and o, p-directing


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