Metabolism of one plamitic acid yields ATPA. 36 ATPB. 56 ATPC. 129 ATP

1.	Metabolism of one plamitic acid yields ATPA. 36 ATPB. 56 ATPC. 129 ATPD. 48 ATP
Answer» Correct Answer - C One plamitic acid, `C_(16)H_(32)O_(2)`, yields eight acetyl CoA molecules seven `(NADH+H^(+),FADH_(2))` through `beta`-oxidation. One acetyl CoA yields 12 ATP in Krebs cycle. One `NADH+" one "FADH_(2)` are equivalent to 5 ATP. The total is `(8xx12)+(7xx5)=131` ATP. Two molecules of ATP are used in initiation of `beta`-oxidation.

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Metabolism of one plamitic acid yields ATPA. 36 ATPB. 56 ATPC. 129 ATPD. 48 ATP

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