1.

Metal 'A'has electronic configuration 2, 8, 1 and metal B' has electronic configuration 2,8, 8, 2. Out of these, which metal is more reactive? Write the reaction of this metal withdilute HCI acid..

Answer»

Metal A is Sodium (Na) : 2,8,1Metal B is Calcium (Ca) : 2,8,8,2.Metal A (Sodium) is more reactive than metal B (Calcium).

Reaction: -i. Sodium metal reacts violently with dilute hydrochloric acid to form sodium chlorides and hydrogen.2Na(s) + 2HCl(aq) → 2NaCl(aq) + H2(g)

ii. Calcium reacts less vigorously to form calcium chloride and hydrogen.Ca + 2HCl → CaCl2 + H2



Discussion

No Comment Found