1.

Metal of heat capacity 50joule per/degree Celsius scale loses 2,000 joule of heat by how much will it temperature fall

Answer» w.k.t 
heat capacity (c) = 50 joules 
amount of heat losses is 2000 joules 

solution :
by specific heat capacity
c=q/∆t 
rearranging the equation 
then we get 
∆t = q/c 
∆t = 2000/50
∆t = 40 k
answer: change in temperature is 40 k 



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