Saved Bookmarks
| 1. |
Metal of heat capacity 50joule per/degree Celsius scale loses 2,000 joule of heat by how much will it temperature fall |
|
Answer» w.k.t heat capacity (c) = 50 joules amount of heat losses is 2000 joules solution : by specific heat capacity c=q/∆t rearranging the equation then we get ∆t = q/c ∆t = 2000/50 ∆t = 40 k answer: change in temperature is 40 k |
|