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Methane undergoes slow atmospheric oxidation and produces carbonmonoxide. If 2xx10^(22) oxygen molecules are used in such oxidation, what weight of methane is consumed? |
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Answer» Solution :Slow atmospheric oxidation of methane is given by the equation `2CH_(4)+3O_(2) to 2CO+4H_(2)O` 3 moles of `O_(2)="2 moles of "CH_(4)` `3 xx 6.022 xx 10^(23) O_(2)` molecules = The weight of `CH_(4)` consumed `(2 xx 16)"GRAMS of "CH_(4)` `2 xx 10^(22) O_(2)` molecules=? The weight of `CH_(4)` consumed `=(2 xx 10^(22) xx 32)/(3 xx 6.022 xx 10^(23))=0.354 G` |
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