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Method 1 of `DeltaU` Temperature of two moles of a monoatomic gas is increased by 600 K in a given process. Find change in internal energy of the gas. |
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Answer» Correct Answer - A Using the equation, `DeltaU=nC_VDeltaT` for change in internal energy `C_V=3/2R` for monoatomic gas `DeltaU=(2)(3/2R)(600)` `=1800R` |
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