Methyl benzoate is prepared by the reaction between benzoic acid and methanol, according to the equation C_(6)H_(5)COOH + CH_(3)OH rightarrow C_(6)H_(5)COOCH_(3) + H_(2)O In an experiment 24.4gm of benzoic acid were reacted with 70.0mL of CH_(3)OH. The density of CH_(3)OH is 0.79 g mL^(-1). The methyl benzoate produced had a mass of 21.6g. What is the percentage yeild of product?

Methyl benzoate is prepared by the reaction between benzoic acid and m

1.	Methyl benzoate is prepared by the reaction between benzoic acid and methanol, according to the equation C_(6)H_(5)COOH + CH_(3)OH rightarrow C_(6)H_(5)COOCH_(3) + H_(2)O In an experiment 24.4gm of benzoic acid were reacted with 70.0mL of CH_(3)OH. The density of CH_(3)OH is 0.79 g mL^(-1). The methyl benzoate produced had a mass of 21.6g. What is the percentage yeild of product?
Answer» 0.917 0.794 0.715 0.217 Answer :B