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Methyl benzoate is prepared by the reaction between benzoic acid and methanol, according to the equation `C_(6)H_(5)COOH + CH_(3)OH rightarrow C_(6)H_(5)COOCH_(3) + H_(2)O` In an experiment 24.4gm of benzoic acid were reacted with 70.0mL of `CH_(3)OH`. The density of `CH_(3)OH` is 0.79 g `mL^(-1)`. The methyl benzoate produced had a mass of 21.6g. What is the percentage yeild of product?A. 0.917B. 0.794C. 0.715D. 0.217 |
Answer» Correct Answer - B |
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