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Methylamine reacts with `HNO_(2)` to form….A. `CH_(3)-0-N=0`B. `CH_(3)-0-CH_(3)`C. `CH_(3)OH`D. `CH_(3)CHO` |
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Answer» Correct Answer - C Methylamine reacts with `HNO_(2)` (nitrous acid) to form methanol. `underset("Methylamine")(CH_(3)-NH_(2))toCH_(3)underset("Methanol")underset(CH_(3)OH)underset(darr)(overset(N_(2))overset(-)(Cl))` |
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