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`Mg+2HCl toMgCl_(2)+H_(2)`. The ration of Mg used to `H_(2)` produced by weight isA. `1:12`B. `12:1`C. `24:1`D. `1:6` |
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Answer» Correct Answer - B `underset(24g)(Mg)+2HCl to MgCl_(2)+underset(2g)(H_(2))` Mass of Mg used: Mass of hydrogen produced `= 24:2=12:1` |
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