Mg can reduce NO_(3)^(-) to NH_(3) in basic solution: NO_(3)^(-) + Mg_((s)) + H_(2)O rarr Mg (OH)_(2(s)) + OH_((aq.))^(-) + NH_(3(g)) A 25.0 mL sample of NO_(3)^(-) solution was treated with Mg. The NH_(3(g))was passed into 50mL to 0.15N HCl. The excessHCl required 32.10 mL of 0.10M NaOH for its neutralisation. What was the molarity of NO_(3)^(-) ions in the originalsample?

Mg can reduce NO_(3)^(-) to NH_(3) in basic solution: NO_(3)^(-) + Mg

1.	Mg can reduce NO_(3)^(-) to NH_(3) in basic solution: NO_(3)^(-) + Mg_((s)) + H_(2)O rarr Mg (OH)_(2(s)) + OH_((aq.))^(-) + NH_(3(g)) A 25.0 mL sample of NO_(3)^(-) solution was treated with Mg. The NH_(3(g))was passed into 50mL to 0.15N HCl. The excessHCl required 32.10 mL of 0.10M NaOH for its neutralisation. What was the molarity of NO_(3)^(-) ions in the originalsample?
Answer» ANSWER :`0.1716`