InterviewSolution
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Microwaves from a transmitter are directed normally toward a plane reflector. A detector moves along the normal to the reflector. Between positions of 14 successive maxima the detector travels a distance 0.14 m. The frequency of the transmitter is `(c = 3 xx 10^(8) m s^(-1))`.A. ` 1.5 xx 10^(10) Hz`B. `10^(10) Hz`C. `3 xx 10^(10) Hz`D. `6 xx 10^(10) Hz` |
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Answer» Correct Answer - A If detector moves ` x` distance , distance from direct sound increases by `x` and distance from reflected sound decreases by `x` so path difference created ` = 2 x` `2 (0.14) = 14 lambda = 14 c//f` `f = ( 14 xx 3 xx 10^(8))/( 0.14 xx 2) = 1.5 xx 10^(10) Hz` |
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