Milkman has a container filled with a mixture of milk and water which

1.	Milkman has a container filled with a mixture of milk and water which are in the ratio of 7 : 3. How many parts of the mixture needs to be removed and replaced from the water to obtain milk and water in ratio of 1 : 1?1. 2/32. 2/73. 2/54. 1/75. None of the above
Answer» Correct Answer - Option 2 : 2/7 Given: Initial ratio of milk to water ratio = 7 : 3 Calculations: Here, let milk in mixture be 7 liters and water be 3 liters ⇒ milk : water = 7 : 3 ⇒ Let, X to be quantity of mixture withdrawn and replaced with water. ⇒ (7 - 7X/10)/(3 - 3X/10 + X) = 1/1 ⇒ 7 - 7X/10 = 3 - 3X/10 + X ⇒ 7 - 3 = 7X/10 - 3X/10 + X ⇒ 4 = 14X/10 ⇒ X = 20/7 ⇒ Total quantity = 10 liters ⇒ Quantity withdrawn = 20/7 × 1/10 ⇒ Quantity withdrawn = 2/7 ∴ 2/7^th of mixture needs to be replaced with water.

Milkman has a container filled with a mixture of milk and water which are in the ratio of 7 : 3. How many parts of the mixture needs to be removed and replaced from the water to obtain milk and water in ratio of 1 : 1?1. 2/32. 2/73. 2/54. 1/75. None of the above

Answer» Correct Answer - Option 2 : 2/7

Given:

Initial ratio of milk to water ratio = 7 : 3

Calculations:

Here, let milk in mixture be 7 liters and water be 3 liters

⇒ milk : water = 7 : 3

⇒ Let, X to be quantity of mixture withdrawn and replaced with water.

⇒ (7 - 7X/10)/(3 - 3X/10 + X) = 1/1

⇒ 7 - 7X/10 = 3 - 3X/10 + X

⇒ 7 - 3 = 7X/10 - 3X/10 + X

⇒ 4 = 14X/10

⇒ X = 20/7

⇒ Total quantity = 10 liters

⇒ Quantity withdrawn = 20/7 × 1/10

⇒ Quantity withdrawn = 2/7

∴ 2/7^th of mixture needs to be replaced with water.

Discussion

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