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Minimum number of capacitors each of `8 muF` and 250 V used to make a composite capacitor of `16 muF` and 1000 V areA. 8B. 32C. 16D. 24

Answer» Correct Answer - B
Minimun number of capacitors in each row ` =(1000)/(250)= 4`
Therefore , 4 capacitors connected in series.
If there are m such rows, that total cacpacity
` = m xx 2 = 16 " "therefore m = 16//2 8`
`therefore` minimum number of capcitors ` = 4 xx 8 = 32`


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