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    				| 1. | Minimum number of capacitors each of `8 muF` and 250 V used to make a composite capacitor of `16 muF` and 1000 V areA. 8B. 32C. 16D. 24 | 
| Answer» Correct Answer - B Minimun number of capacitors in each row ` =(1000)/(250)= 4` Therefore , 4 capacitors connected in series. If there are m such rows, that total cacpacity ` = m xx 2 = 16 " "therefore m = 16//2 8` `therefore` minimum number of capcitors ` = 4 xx 8 = 32` | |