1.

…….ml (volume ) is required of or 10 volume H_2O_2 of 2N KMnO_4 in acidic medium ?

Answer»

200 ML
100 ml
224 ml
150 ml

Solution :`N=V/5.6=10/5.6`= 1.7857 N `H_2O_2`
`N_1V_1(H_2O_2) = N_2V_2(KMnO_4)`
`V_1=(2xx200)/1.7857`=224 ml of `H_2O_2`


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