1.

MnO_(2)+4HClrarrMnCl_(2)+Cl_(2)+2H_(2)O, In the reaction MnO_(2) acts as

Answer»

0.80 mole of `Cl_(2)` is formed
0.80 mole of HCl REMAINS unreacted
`MnO_(2)` is completely reacts
`MnO_(2)` is the LIMITING reactant

Solution :`146g=4` moles
`implies MnO_(2)` is limiting reagent
`MnO_(2)+4HClrarrMnCl_(2)+Cl_(2)+2H_(2)O`
`0.8+4xx0.8rarr0.8`


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