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MnO_(4)^(2-) underges disproportionation rection in acidic medium but MnO_(4)^(-) does not give reason |
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Answer» Solution :In `MnO_(4)^(-)`Mn is in the highest oxidation state of +7 and hence it can undergo disproportionation In contrast the O.N of Mn in `MnO_(4)^(-)`is +6 therefore it can increase its O.Nto +7 or DECREASE its cannot to some lower value thus `MnO_(4)^(2-)`undergoes DISPORPORTIONATION according to the following reactio `3MnO_(4)^(2-)+4H^(+)rarr2MnO_(4)^(-)+MnO_(2)^(-)+2H_(2)O` here the O.N of Mn increase from +6 in `MnO_(4)^(2-)` to +7 in `MnO_(4)^(-)` and decreases to +4 in `MnO_(2)` thus `MnO_(4)^(2-)` undergoes disproportionation in acidic medium |
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