`MnO_(4)^(-)` ions are reduced in acidic conditions to `Mn^(2+)` ions whereas they are reduced in neutral condition to `MnO_(2)`. The oxidation of 25 mL of a solution `x` containing `Fe^(2+)` ions required in acidic condition 20 mL of a solution y containing `MnO_(4)` ions. What value of solution y would be required to oxidize 25 mL of solution x containing `Fe^(2+)` ions in neutral condition ?A. 11.4 mLB. 12.0 mLC. 33.3 mLD. 35.0 mL

`MnO_(4)^(-)` ions are reduced in acidic conditions to `Mn^(2+)` ions

1.	`MnO_(4)^(-)` ions are reduced in acidic conditions to `Mn^(2+)` ions whereas they are reduced in neutral condition to `MnO_(2)`. The oxidation of 25 mL of a solution `x` containing `Fe^(2+)` ions required in acidic condition 20 mL of a solution y containing `MnO_(4)` ions. What value of solution y would be required to oxidize 25 mL of solution x containing `Fe^(2+)` ions in neutral condition ?A. 11.4 mLB. 12.0 mLC. 33.3 mLD. 35.0 mL
Answer» Correct Answer - C `overset(+7)(MnO_(4)^(-))+5e^(-)overset(H+)(rarr)overset(+2)(Mn^(2+))` `overset(+7)(MnO_(4)^(-))+3e^(-)overset(("neutral"))(rarr)overset(+4)(MnO_(2))` `:.` 20 mL of `MnO_(4)^(-)(H^(+))` `-=(20xx5)/(3)"mL of " MnO_(4)^(-)` (neural) `:. y=33.33 mL`

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