Mno42- (1 mole ) in neutral aqueous medium is disproportionate to�

1.	Mno42- (1 mole ) in neutral aqueous medium is disproportionate to A) 2/3 mole of mno4- and 1/3 mole of mno2B) 1/3 mole of mno4- and 2/3 mole of mno2Is there is another way to solve this question without balancing and writing the whole equation. Is there is shortcut to do this question by oxidation state only .
Answer» Here MnO4^2- where Mn is in +6 state disproportionates to MnO₄^1-(where Mn is in +7) andMnO₂ (where Mn is in+4). So The changes are +6 -> +7 => 1 unit increase +6 -> +4 => 2 unit decrease So to balance the redox process the ratio of number of moles of the species produced should be MnO₄^2-: MnO₂ = 2 :1 So the statement (A) supports above fact

Mno42- (1 mole ) in neutral aqueous medium is disproportionate to A) 2/3 mole of mno4- and 1/3 mole of mno2B) 1/3 mole of mno4- and 2/3 mole of mno2Is there is another way to solve this question without balancing and writing the whole equation. Is there is shortcut to do this question by oxidation state only .

Answer»

Here MnO4^2- where Mn is in +6 state disproportionates to MnO₄^1-(where Mn is in +7) andMnO₂ (where Mn is in+4). So The changes are

+6 -> +7 => 1 unit increase

+6 -> +4 => 2 unit decrease

So to balance the redox process the ratio of number of moles of the species produced should be

MnO₄^2-: MnO₂ = 2 :1

So the statement (A) supports above fact

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