Moderators⭐ Branily star ❤️ other best user Question

1.	Moderators⭐ Branily star ❤️ other best user Question
Answer» $\: \: \: \huge{\underline{\underline{\textsf{\maltese{\red{answer}}}}}}$ 1) a + ( b + c ) = ( a + b ) + c Substitute the values, ->-25+ [20+ (-10) = [(-25) +20] + (-10) Solve the RHS with brackets first, Solve the LHS with brackets first, →-25 + 10 = [(-25) +20] + (-10) ADD the integers in LHS, →-15= [(-25) +20] + (-10) ->-15=(-5)+ (-10) Add the integers in RHS, -> -15= -15 Comparing both sides, LHS = RHS .Thus, verified. __________________________ 2) a × (b + c) = a × b +a × c Solution: Substitute the values, ->-25 x [20+ (-10)] = (-25) × 20 + (-25) × (-10) Solve the LHS with brackets first, ->-25 x 10 = (-25) 20+ (-25) (-10) MULTIPLY the integers, ->250 = (-25) x 20 + (-25) × (-10) Solve the RHS using BODMAS RULE, →> -250 = -500 + 250 Add the integers, ->-250 = -250 Comparing both sides, + LHS = RHS Thus, verified. ________________________ hope it was helpful to you

Answer»

$\: \: \: \huge{\underline{\underline{\textsf{\maltese{\red{answer}}}}}}$

1) a + ( b + c ) = ( a + b ) + c

Substitute the values,

->-25+ [20+ (-10) = [(-25) +20] + (-10)

Solve the RHS with brackets first,

Solve the LHS with brackets first,

→-25 + 10 = [(-25) +20] + (-10)

ADD the integers in LHS,

→-15= [(-25) +20] + (-10)

->-15=(-5)+ (-10) Add the integers in RHS,

-> -15= -15

Comparing both sides,

LHS = RHS

.Thus, verified.

__________________________

2) a × (b + c) = a × b +a × c

Solution: Substitute the values,

->-25 x [20+ (-10)] = (-25) × 20 + (-25) × (-10)

Solve the LHS with brackets first,

->-25 x 10 = (-25) 20+ (-25) (-10)

MULTIPLY the integers,

->250 = (-25) x 20 + (-25) × (-10)

Solve the RHS using BODMAS RULE,

→> -250 = -500 + 250

Add the integers, ->-250 = -250

Comparing both sides,

+ LHS = RHS

Thus, verified.

________________________

hope it was helpful to you