Moderators⭐ Branily star ❤️ other best user Question

1.	Moderators⭐ Branily star ❤️ other best user Question
Answer» Explanation: Let M be the minimum MOLECULAR weight of the compound. 7% of the compound is sodium. It is equal to $\frac{7}{100} \times m = 0.07mg$ sodium in 1 mole of compound. At LEAST, 1 mole of NA will be present in 1 mole of compound. 1 mole of sodium weighs 23 g. $m = \frac{23}{0.07} = 329g\mol$ Thus, 0.07M =23Thus, the minimum molecular weight of the compound is 329 g/mol. Hence, the correct option is C

Answer»

Explanation:

Let M be the minimum MOLECULAR weight of the compound.

7% of the compound is sodium. It is equal to

$\frac{7}{100} \times m = 0.07mg$

sodium in 1 mole of compound.

At LEAST, 1 mole of NA will be present in 1 mole of compound.

1 mole of sodium weighs 23 g.

$m = \frac{23}{0.07} = 329g\mol$

Thus, 0.07M =23Thus, the minimum molecular weight of the compound is 329 g/mol.

Hence, the correct option is C

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