Saved Bookmarks
| 1. |
Mohan starts from a point A at 5 : 00 am at the speed of 20 km per hour and from the same point other Rohan starts at 8 : 00 am at the speed of 60 km per hour. Quantity I: If both meet each other at other point C and return immediately towards point A. How much total time the Mohan will take go and return immediately to the point A?Quantity II: 9 hours 1. Quantity 1 > Quantity 22. Quantity 1 ≥ Quantity 23. Quantity 1 < Quantity 24. Quantity 1 ≤ Quantity 25. Quantity 1 = Quantity 2 |
|
Answer» Correct Answer - Option 5 : Quantity 1 = Quantity 2 Given: Speed of mohan = 20 km/hr initially Speed of rohan = 60 km/hr Formula used: Distance = speed × time Calculation: The distance travelled by Mohan in first 3 hours = 3 × 20 = 60 km ⇒ the relative speed of X and Y = 60 – 20 = 40 km per hour ⇒ 60 = 40 × y ⇒ y = 1.5 hours ⇒ It means after 1.5 hours the Rohan meets Mohan. Quantity I: The total time taken by A to go and return immediately = 3 + 1.5 + 3 + 1.5 ⇒ Total time taken = 9 hours Quantity II: 9 hours ∴ Quantity I = Quantity II |
|