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Molar conductivities at infinite dilution of Mg2+ and Br- are 105.8 Ω cm2 mol-1 and 78.2 Ω-1 cm2 mol-1 respectively. Calculate molar conductivity at zero concentration of MgBr2. |
Answer» Given : \(\lambda^0_{Mg^{2+}}\)= 105.8 Ω-1 cm2 mol-1 \(\lambda^0_{Br^-}\) = 78.2 Ω-1 cm2 mol-1 \(∧_{0(MgBr_2)}\) = ? By Kohlrausch’s law, \(∧_{0(MgBr_2)}\) = \(\lambda^0_{Mg^{2+}}\) + \(2\lambda^0_{Br^-}\) = 105.8 + 2 × 78.2 = 105.8 + 156.4 = 262.2 Ω-1 cm2 mol-1 ∴ Molar conductivity of MgBr2 at zero concentration = \(∧_{0(MgBr_2)}\) = 262.2 Ω-1 cm2 mol-1 |
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