1.

Molar heat capacity at constant volume is …………….

Answer»

Solution :According to the FIRST law of thermodynamics,
dy = dU + PdV
Dividing both sides by dT , we have
`(dq)/(dT)="(dU+PdV)"/(dT)`
At constant VOLUME dV=0 , then
`(dq)/(dT)=((dU)/(dT))_(v)`
`C_V=((dU)/(dT))_V`
THUS the heat capacity at constant volume `(C_V)` is DEFINED as the rate of CHANGE of inter energy with respect to temperature at constant volume.


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