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Molar heat capacity at constant volume is ……………. |
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Answer» Solution :According to the FIRST law of thermodynamics, dy = dU + PdV Dividing both sides by dT , we have `(dq)/(dT)="(dU+PdV)"/(dT)` At constant VOLUME dV=0 , then `(dq)/(dT)=((dU)/(dT))_(v)` `C_V=((dU)/(dT))_V` THUS the heat capacity at constant volume `(C_V)` is DEFINED as the rate of CHANGE of inter energy with respect to temperature at constant volume. |
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