Molarity of a solution obtained by mixing 800 mL of 0.6 M HCl with 200

1.	Molarity of a solution obtained by mixing 800 mL of 0.6 M HCl with 200 mL of 1 M HCl will be(a) 0.4 M(b) 1.6 M(c) 0.68 M(d) 1.68 M
Answer» Answer is : (c) 0.68 M M = \(\frac{M_1V_1+M_2V_2}{V_1+V_2}\) \(=\frac{0.6\times 800+1\times 200}{1000}\) \(=\frac{480+200}{1000}\) \(=\frac{680}{1000}\) = 0.68 M

Molarity of a solution obtained by mixing 800 mL of 0.6 M HCl with 200 mL of 1 M HCl will be(a) 0.4 M(b) 1.6 M(c) 0.68 M(d) 1.68 M

Answer»

Answer is : (c) 0.68 M

M = \(\frac{M_1V_1+M_2V_2}{V_1+V_2}\)

\(=\frac{0.6\times 800+1\times 200}{1000}\)

\(=\frac{480+200}{1000}\)

\(=\frac{680}{1000}\)

= 0.68 M

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Molarity of a solution obtained by mixing 800 mL of 0.6 M HCl with 200 mL of 1 M HCl will be(a) 0.4 M(b) 1.6 M(c) 0.68 M(d) 1.68 M

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