1.

Molarity of `H_(2)SO_(4)` is `18 M`. Its density is `1.8 g//cm^(3)`, hence molaity is :A. `18`B. `100`C. `36`D. `500`

Answer» Correct Answer - D
molarity
`(Mxx1000)/(1000d-MM_(w))=(18xx1000)/(1000xx1.8-18xx98)=500`


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