1.

Molarity of `H_(2)SO_(4)` is `18 M`. Its density is `1.8 g//cm^(3)`, hence molality is :A. 36B. 200C. 500D. 18

Answer» Correct Answer - C
Molality (m) = `("Molarity")/("Density"-("Molarity " xx " Molecular mass")/(1000))`
`=(18)/(1.8-(18xx98)/(1000))=500`.


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