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Moldydenum `("At. mass=96g//mol"^(-1))` crystallizes as bcc crystal. If density of crystal is `10.3g//cm^(3)`, then radius of Mo atoms `(use N_(A)= 6 xx 10^(23))`:A. 11pmB. 314pmC. 135.96pmD. None of these |
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Answer» Correct Answer - C `d=(ZxxM)/(a^(3)xxN_(A))` `10.3=(2xx96)/(a^(3)xx6xx10^(23))` `a=3.14xx10^(-8)cm=314"pm"` `r=sqrt(3a)/(4)=135.96 "pm"` |
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