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Mole fraction of glucose in 18% (wt./wt.) solution of glucose isA. 0.18B. 0.1C. 0.017D. 0.021 |
Answer» Correct Answer - D Glucose =18 g, Solution =100g :. Water = 100-18=82g Mole freaction of glucose `=(18//180)/(18//180+82//18` `=0.1/(0.1+4.56)=0.1/4.66=0.021 |
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