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Mole fraction of solute in a 2.0 molal aqueous solution is : |
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Answer» 1.77 No. of moles of SOLUTE = 2 MOL No. of moles water `= ((1000G))/(("18 g mol"^(-1)))=55.55` mol Mole FRACTION of solute `= (("2 mol"))/(("2 mol")+("55.55 mol"))=0.347`. |
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