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Mole fraction of the solute in a 1.00 molar aqueous solution is |
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Answer» 1.00M means that1 mole of soluteis dissolved in1L of solution Molar mass of water=18. Therefore 1kg of water =1000/18mol = 55.6mol Therefore mole fraction of the solute is1/(55.56+1)=1/(55.56+1)=0.0177 |
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