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Mole fraction of x M aqueous urea solution is : [Given : density of solution is `d gm//ml` ]A. `(18x)/(1000d - 42 x)`B. `(18 x)/(1000d - 60x)`C. `(18x)/(1000d - 18x)`D. None of these |
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Answer» Correct Answer - A x moles of Urea in 1000 ml of solution mass of solution = 1000 d gm mass of solute `60 x gm` mass of solvent `= (1000d - 60x) gm` Mole fracction of urea `= (x)/(x + ((1000d - 60x)/(18)))` `= (18x)/(18x + 1000d - 60x)` `x_("urea") = (18x)/(1000d - 42x)` |
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