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Mole of electrons present in 9g aluminium is |
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Answer» Number of moles of 9 g of Al3+ ion = {tex}\\frac{9}{27}{/tex}(given mass/molar mass)Now, number of ions of Al3+ = {tex}\\frac 13 \\times 6.022 \\times 10^{23}{/tex}= 2.007\xa0{tex}\\times{/tex}\xa01023(number of ions/atoms/molecules=Avogadro\'s number*number of moles)Now, number of electrons in 1 ion of Al3+ = 10So, 2.007\xa0{tex}\\times{/tex}\xa01023 ions will have 2.007\xa0{tex}\\times{/tex}\xa01023{tex}\\times{/tex}\xa010 = 2.007\xa0{tex}\\times{/tex}\xa01024\xa0 electrons. Hi Esha Pal Hlo amira Its ans is 4.33 but i donot know how |
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